# How to Use a Soroban Abacus

The sorabon abacus is a able artful apparatus abiding in over 500 years of history. It is still acclimated to this day for its acumen as able-bodied as its educational amount for all ages and the visually impaired. Afterwards acquirements the basics of counting on the soroban abacus, you will be able to bound accomplish accession like addition, subtraction, multiplication, and division. |

Part 1 Counting

## 1. Position your abacus and absence your beads

Each cavalcade has one bean in the top row, and four chaplet in the bottom. All of the top row chaplet should be in the up position, and bottomward in the basal row. This is the absence position for anniversary column. Anniversary bean in the top row represents a amount of 5 and anniversary bean in the basal row represents a amount of 1.

## 2. Accredit anniversary cavalcade a abode value

Each cavalcade of chaplet represents a abode value. Starting from the appropriate are the "ones" place, to its larboard is the "tens" place, followed by the “hundreds”, “thousands” and so on.

You can additionally accredit columns to be decimal places. For example, if you are apery a cardinal like 12.5, again the extreme appropriate cavalcade would be the “tenths” abode (the aboriginal decimal place), to its larboard would be the “ones” place, followed by the “tens” place.

Likewise, to represent a cardinal like 12.55, the extreme appropriate cavalcade would be the “hundredths” place, to its larboard would be the “tenths” place, followed by the “ones” place, and again the “tens” place.

## 3. Counting 1 to 4 in the basal row

Start with the “ones” column. The cardinal "one" would be represented by blame up a distinct bean from the basal row, area anniversary bean represents a amount of 1. Advance up two chaplet for "two", etc.

A pro tip for accelerated arithmetic: use your deride to dispense chaplet in the basal row and your basis feel for chaplet in the top.

## 4. Counting 5 to 9 application both rows

The top row bean represents a amount of 5. To announce the cardinal “five”, advance the bean from the top row to the "down" position (a amount of 5), and advance all four chaplet from the basal row bottomward (a amount of 0), for a absolute amount of 5.

To calculation to "six," advance one bean from the basal row up. Calm the top row (a amount of 5) and the basal row (a amount of 1), this represents a absolute amount of 6. Advance up added chaplet from the basal row to abide the count.

## 5. Echo the arrangement for anniversary abode value

The action is the aforementioned beyond the abacus to announce a chiffre for anniversary abode value.

To go from "nine” to "ten”, the ones cavalcade is set to the absence position of “zero” (top row bean up, basal row chaplet down), and the tens cavalcade is set to “one” (top row bean up, one bean up in the basal row). Account the abacus larboard to appropriate would be the digits 1, 0, or “ten”.

“Eleven” would accept one bean from the basal row in the tens cavalcade pushed up, and addition bean from the basal of the ones cavalcade pushed up. The digits would apprehend 1, 1, or “eleven”

Continuing into the hundreds, thousands, and so on, artlessly position 0 to 9 in anniversary abode cavalcade to announce the chiffre of the abode value.

# Part 2 Abacus and Subtracting

## 1. Band up your aboriginal number

Let’s add 2,145 and 5,668. Aboriginal displace your abacaus to absence position. Again access 2,145 on the abacus by blame bottomward a top row bean in the “ones” column, advance up four basal row chaplet in the “tens”, one in the “hundreds”, and two in the “thousands”.

## 2. Alpha abacus from the better abode value

The aboriginal numbers you'll add are the 5 to the 2 from the “thousands” column. Advance a distinct bean from the top row of that cavalcade bottomward and accumulate the two chaplet from the basal row up. The “thousands” cavalcade is now a 7 digit.

Likewise, add 6 to the 1 in the hundreds place. Move the top row bean in the “hundreds” cavalcade bottomward and advance addition basal row bean up to for a 7 digit.

## 3. Accustomed over

Adding 6 to the 4 in the “tens” cavalcade will aftereffect in 10. You'll backpack over a 1 to the “hundreds”, authoritative the 7 an 8 in that column. Next, advance all the chaplet bottomward in the “tens”, authoritative the chiffre a 0.

In the ones column, 5 additional 8 equals 13, so you'll backpack a 1 over to the “tens” column, authoritative the 0 chiffre a 1. Advance the top row bean up in the “ones” column, and three chaplet up from the bottom, authoritative the “ones” cavalcade chiffre a 3.

## 4. Apprehend the columns to get the answer

To recap, you now accept a 7 in the “thousands” column, an 8 in the “hundreds”, a 1 in the “tens”, and a 3 in the “ones”: 2,145 5,668 = 7,813.

## 5. Decrease by accomplishing the action in reverse

Let’s subract 788 from 845. Access 845 on the abacus and alpha adding from the better abode amount cavalcade and borrow digits from the antecedent cavalcade instead of accustomed them over.

• 7 from 8 is 1, so move the top row bean up and leave a distinct bean from the basal row up in the hundreds place.

• In the tens place, you can't decrease 8 from 4, so you'll borrow the 1 in the hundreds abode (leaving it zero) and decrease 8 from 14, authoritative it 6 in the tens abode (one bean bottomward in the top row and one bean up in the lower).

• Do the aforementioned in the ones place, "borrowing" a bean from the tens abode authoritative the tens abode go from a 6 to a 5. Decrease 8 from 15 authoritative the ones abode a 7.

• Apprehend the acknowledgment to 845 - 788, from larboard to right: 57.

# Part 3 Multiplying

## 1.Record the problem

Let’s accumulate 43 and 13. Alpha at the extreme larboard cavalcade of the abacus and accredit columns to "4", "3", absence position for "x", "1", "3", and absence position for "=". Leave the actual columns in the absence position as able-bodied for recording the solution.

## 2.Multiply by alternating columns

Multiplication is burst bottomward by adding anniversary chiffre in the botheration in an alternating cavalcade sequence:**a)** Accumulate the * tens* cavalcade by the

*cavalcade afterwards the x.*

**tens****b)**Accumulate the

*cavalcade by the*

**tens***cavalcade afterwards the x.*

**ones****c)**Accumulate the

*cavalcade by the*

**ones***cavalcade afterwards the x.*

**tens****d)**Accumulate the

*cavalcade by the*

**ones***cavalcade afterwards the x.*

**ones**For adding numbers with added abode values, chase the aforementioned arrangement of starting with the leftmost digits, and alive to the right.

## 3. Almanac the products

Record the artefact of the alternating cavalcade multiplication in the acknowledgment columns, starting afterwards the "=" column. For the botheration 43 x 13:**a)** Accumulate 4 and 1, recording the artefact 4 in the aboriginal acknowledgment column. Advance four basal row chaplet up in that seventh column.**b)** Accumulate 4 and 3, recording the artefact 12 in the eighth column. Advance two basal row chaplet up to almanac a 2. Backpack over a 1 to the antecedent seventh column, alteration the chiffre from a 4 to a 5 by blame the top row bean and all the basal row chaplet down.**c)** Accumulate 3 and 1, recording the artefact 3 in the eighth cavalcade by abacus it to the absolute 2. 3 2 = 5. Advance the top row bean bottomward and all the basal row chaplet down, for the chiffre 5.**d)** Accumulate 3 and 3, recording the artefact 9 in the ninth column. Advance the top row bean bottomward and all the basal row chaplet up.

Read your acknowledgment from larboard to appropriate in the artefact columns afterwards the “=”: 559.

# Part 4 Dividing

## 1. Almanac the problem

Let’s bisect 78 by 3. The recording adjustment starting from the extreme larboard cavalcade is the divisor, followed by quotient, and again the dividend:

• In the extreme larboard cavalcade accredit the divisor “3”.

• Affective to the right, leave the caliber columns in absence position. The cardinal of columns for the caliber should be the cardinal of places in the dividend. In this case the allotment is 78, which has two places, accordingly leave two columns in absence position.

• Afterward the caliber columns, almanac the allotment columns 7 and 8.

• If you like, you can add an added cavalcade in absence position amid the divisor and the caliber columns, and amid the allotment and caliber columns. This can advice you analyze the caliber as you assignment through the problem.

## 2. Almanac the aboriginal caliber digit

Divide the aboriginal cardinal in the allotment (7) by the divisor (3), and put it in the aboriginal caliber column. 3 goes into 7 twice, so almanac a 2 there. Advance two basal row chaplet up in the aboriginal caliber column.

## 3. Actuate the butt and record

Next, accumulate the caliber in the aboriginal caliber cavalcade (2) by the aboriginal divisor cavalcade (3). The artefact (6) needs to be subtracted from the aboriginal allotment cavalcade (7), to get the butt (1). Advance the top row bean up and leave one basal row bean up, so that the 7 becomes a 1. The allotment columns should now apprehend 18.

## 4. Echo the process

Record the abutting chiffre of the quotient, by adding the abutting cardinal in the allotment including the butt to its larboard (18) by the divisor (3). 18 disconnected by 3 is 6.

• In the additional caliber column, advance up one top row bean bottomward and one basal row bean up, for the chiffre 6.

• Apprehend your caliber from larboard to appropriate to get your answer: 26.

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